What mass of 95% pure $CaCO_3$ will be required to neutralise 50 mL of 0.5 M HCl solution according to the following reaction? $CaCO_{3}(s)$ + 2HCl(aq) → $CaCl_{2}(aq)$ + $CO_{2}(g)$ + $2H_{2}O(l)$ [Calculate upto second place of decimal point]