Chemistry2022easy

Nernst Equation

Find the emf of the cell Ni(s)+2Ag+(0.001M)>Ni2+(0.001M)+2Ag(s){Ni(s) + 2Ag^{+} (0.001 M) -> Ni^{2+} (0.001 M) + 2Ag(s)} (Given that Ecell=1.05V,2.303RTF=0.059E^{\circ}cell = 1.05\, \text{V}, \frac{2.303RT}{F} = 0.059 at 298 K)

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